Laurent expansion
On an annulus of holomorphicity about a, f has a unique convergent expansion Σₙ∈ℤ cₙ(z−a)ⁿ.
REFERENCE SHEET
The coefficient of (z−a)⁻¹ records the local contribution to a contour integral.
Before this Contour integration & Cauchy formulas
On an annulus of holomorphicity about a, f has a unique convergent expansion Σₙ∈ℤ cₙ(z−a)ⁿ.
Removable if all negative Laurent coefficients vanish; a pole if finitely many are nonzero; essential if infinitely many are nonzero.
Res(f,a)=c₋₁. At a simple pole, it is limz→a (z−a)f(z).
If f is holomorphic on a neighborhood of a positively oriented piecewise smooth simple closed contour and its interior except for finitely many isolated singularities inside, its integral is 2πi times their residue sum.
If g,h are holomorphic near a, h(a)=0, h′(a)≠0, and g(a)≠0, then Res(g/h,a)=g(a)/h′(a).
A holomorphic function on a punctured neighborhood of a that is bounded near a extends holomorphically across a.
Suitable complex contours can evaluate real integrals; estimates must justify any arc contributions being discarded.
Contour integrals recover power-series coefficients and support generating-function methods.
01 / Compute
The denominator derivative is 2z.
The simple-pole formula gives 1/(2i).
02 / Classify
Use the power series for sine.
sin(z)/z=1−z²/3!+⋯. The singularity is removable with extension value 1; there is no z⁻¹ term, so the residue is 0.
Further reading and full-length treatments: